What is NQT?
TCS NQT is a multi-level assessment conducted to determine if a graduate has the following competencies and skills that are required by companies while recruiting freshers: Competence on the core cognitive processes required for entry-level jobs, industry-specific knowledge and insights, and specialization on skills required to perform various job roles.
TCS NQT Aptitude 60 Questions with Answers And explanation
Q1. In a potato race, 20 potatoes are placed in a line of intervals of 4 meters with the first potato 24 meters from the starting point. A contestant is required to bring the potatoes back to the starting place one at a time. How far would he run in bringing back all the potatoes?
Ans. C. 2480
Given, a total number of potatoes = 20.
First potato 24 meters from the
starting point. There are 4 meters
in the intervals.
A contestant is required to bring
the potatoes back to the starting
place one at a time. So for the first potato,
he has to travel 48 meters, for the second 56 meters …
a = 48, d= 8, n = 20.
Sum of n terms in A.P = Sn=n/2[2a+(n−1)d]
∴ 2480 meters he run in bringing back all the potatoes.
Q2. problemsolvingproblemsolvingprob . . . . . . Find the 2015th term in the series?
Ans. A. n
Problemsolving = 14 letter word.
So divide 2015 by 14 and find the remainder.
Here remainder is 13. so 13th letter in problemsolving is ‘n’.
Q3. 0.397 /(1.2×1.2+0.66+1.1×1.1)= ?
Ans A. 0.1
Q4. What is the sum of all the two-digits numbers which when divided by 7 gives a remainder of 3 ?
Ans C. 676
The First Two-Digit Number, which is divided by 7 and gives the remainder 3, will be 10.
The last Two-Digit Number, which is divided by 7 and gives the remainder 3, will be 94.
The common difference between two consecutive numbers will be 7.
This series will be like →10, 17, 24,………………………. 94.
Here First Number a = 10, Last number tn = 94, Common Difference d = 7 ;
Using the Formula for Last Number tn = a + (n – 1) x d;
⇒ a + (n – 1) x d = tn
Put the value of a , d and tn in above equation.
⇒ 10 + (n – 1) x 7 = 94
⇒ 10 + 7n – 7 = 94
or 7n + 3 = 94
⇒ 7n = 94 – 3 = 91
or n = 91/7
⇒ n = 13
Using the formula for the sum of Arithmetic Progression.
Sn = n/2 [ First Number + Last Number ] ;
Put the value of n, First Number, and Last Number, we will get,
Sn = 13/2 [ 10 + 94 ]
Sn = 104 x 13/2
.or Sn = 52 x 13
Sn = 676
Want more Buy Our PDf ….
Buy TCS NQT Aptitude Questions with Answers And explanation [60 Questions] 2021. Every topic covered and each topic have 2 to 5 questions
Also if you want to Practice Interview questions with us on call or zoom video call, Let me know. Send your details on the below email, We will charge for this but it will help you a lot in every way.
How to access this PDF after payments?
- You are one step ahead to achieve your dream job.
- Send me the screenshot of your Receipt, with Phone no. and Name.
- On this mail firstname.lastname@example.org.
- Write the PDF name in the subject.
- After receiving your mail, we will send you this PDF within Half Hour.
Note: If you are facing any problem at any steps, feel FREE to contact Us. on above mail.
BUY Accenture Technical round Question [ TOP 40 Question ] Click here
join telegram group for more related Documents Join Now